Ignore:
Timestamp:
Jul 19, 2002, 11:51:34 AM (22 years ago)
Author:
lmdzadmin
Message:

Modifications de JLD sur la conservation de l'energie
On supprime les modifs de Pascale sur le cdrag, elles refroidissaient trop
l'atmosphere
LF

File:
1 edited

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  • LMDZ.3.3/branches/rel-LF/libf/phylmd/radlwsw.F

    r367 r393  
    3939#include "dimphy.h"
    4040#include "raddim.h"
     41#include "YOETHF.h"
    4142c
    4243      real rmu0(klon), fract(klon), dist
     
    8889      REAL*8 ztopsw0(kdlon), ztoplw0(kdlon)
    8990      REAL*8 zsolsw0(kdlon), zsollw0(kdlon)
    90 
     91      REAL*8 zznormcp
    9192c
    9293c-------------------------------------------
     
    215216      ENDDO
    216217      DO k = 1, kflev
     218c      DO i = 1, kdlon
     219c         heat(iof+i,k) = zheat(i,k)
     220c         cool(iof+i,k) = zcool(i,k)
     221c         heat0(iof+i,k) = zheat0(i,k)
     222c         cool0(iof+i,k) = zcool0(i,k)
     223c      ENDDO
    217224      DO i = 1, kdlon
    218          heat(iof+i,k) = zheat(i,k)
    219          cool(iof+i,k) = zcool(i,k)
    220          heat0(iof+i,k) = zheat0(i,k)
    221          cool0(iof+i,k) = zcool0(i,k)
     225C        scale factor to take into account the difference between
     226C        dry air and watter vapour scpecific heat capacity
     227         zznormcp=1.0+RVTMP2*PWV(i,k)
     228         heat(iof+i,k) = zheat(i,k)/zznormcp
     229         cool(iof+i,k) = zcool(i,k)/zznormcp
     230         heat0(iof+i,k) = zheat0(i,k)/zznormcp
     231         cool0(iof+i,k) = zcool0(i,k)/zznormcp
    222232      ENDDO
    223233      ENDDO
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