source: trunk/LMDZ.GENERIC/libf/phystd/dsolver.F @ 3436

      SUBROUTINE DSOLVER(NL,GAMA,CP,CM,CPM1,CMM1,E1,E2,E3,E4,BTOP,
     *                   BSURF,RSF,XK1,XK2)

C  GCM2.0  Feb 2003
C
C DOUBLE PRECISION VERSION OF SOLVER

!!      PARAMETER (NMAX=201)
      IMPLICIT REAL*8  (A-H,O-Z)
      DIMENSION GAMA(NL),CP(NL),CM(NL),CPM1(NL),CMM1(NL),XK1(NL),
     *          XK2(NL),E1(NL),E2(NL),E3(NL),E4(NL)
      DIMENSION AF(2*NL),BF(2*NL),CF(2*NL),DF(2*NL),XK(2*NL)
C*********************************************************
C* THIS SUBROUTINE SOLVES FOR THE COEFFICIENTS OF THE    *
C* TWO STREAM SOLUTION FOR GENERAL BOUNDARY CONDITIONS   *
C* NO ASSUMPTION OF THE DEPENDENCE ON OPTICAL DEPTH OF   *
C* C-PLUS OR C-MINUS HAS BEEN MADE.                      *
C* NL     = NUMBER OF LAYERS IN THE MODEL                *
C* CP     = C-PLUS EVALUATED AT TAO=0 (TOP)              *
C* CM     = C-MINUS EVALUATED AT TAO=0 (TOP)             *
C* CPM1   = C-PLUS  EVALUATED AT TAOSTAR (BOTTOM)        *
C* CMM1   = C-MINUS EVALUATED AT TAOSTAR (BOTTOM)        *
C* EP     = EXP(LAMDA*DTAU)                              *
C* EM     = 1/EP                                         *
C* E1     = EP + GAMA *EM                                *
C* E2     = EP - GAMA *EM                                *
C* E3     = GAMA*EP + EM                                 *
C* E4     = GAMA*EP - EM                                 *
C* BTOP   = THE DIFFUSE RADIATION INTO THE MODEL AT TOP  *
C* BSURF  = THE DIFFUSE RADIATION INTO THE MODEL AT      *
C*          THE BOTTOM: INCLUDES EMMISION AND REFLECTION *
C*          OF THE UNATTENUATED PORTION OF THE DIRECT    *
C*          BEAM. BSTAR+RSF*FO*EXP(-TAOSTAR/U0)          *
C* RSF    = REFLECTIVITY OF THE SURFACE                  *
C* XK1    = COEFFICIENT OF THE POSITIVE EXP TERM         *
C* XK2    = COEFFICIENT OF THE NEGATIVE EXP TERM         *
C*********************************************************

C======================================================================C

      L=2*NL
 
C     ************MIXED COEFFICENTS**********
C     THIS VERSION AVOIDS SINGULARITIES ASSOC.
C     WITH W0=0 BY SOLVING FOR XK1+XK2, AND XK1-XK2.

      AF(1) = 0.0
      BF(1) = GAMA(1)+1.
      CF(1) = GAMA(1)-1.
      DF(1) = BTOP-CMM1(1)
      N     = 0
      LM2   = L-2

C     EVEN TERMS
 
      DO I=2,LM2,2
        N     = N+1
        AF(I) = (E1(N)+E3(N))*(GAMA(N+1)-1.)       
        BF(I) = (E2(N)+E4(N))*(GAMA(N+1)-1.)
        CF(I) = 2.0*(1.-GAMA(N+1)**2)
        DF(I) = (GAMA(N+1)-1.) * (CPM1(N+1) - CP(N)) +
     *            (1.-GAMA(N+1))* (CM(N)-CMM1(N+1))
      END DO
 
      N   = 0
      LM1 = L-1
      DO I=3,LM1,2
        N     = N+1
        AF(I) = 2.0*(1.-GAMA(N)**2)
        BF(I) = (E1(N)-E3(N))*(1.+GAMA(N+1))
        CF(I) = (E1(N)+E3(N))*(GAMA(N+1)-1.)
        DF(I) = E3(N)*(CPM1(N+1) - CP(N)) + E1(N)*(CM(N) - CMM1(N+1))
      END DO
 
      AF(L) = E1(NL)-RSF*E3(NL)
      BF(L) = E2(NL)-RSF*E4(NL)
      CF(L) = 0.0
      DF(L) = BSURF-CP(NL)+RSF*CM(NL)
 
      CALL DTRIDGL(L,AF,BF,CF,DF,XK)
 
C     ***UNMIX THE COEFFICIENTS****

      DO 28 N=1,NL
        XK1(N) = XK(2*N-1)+XK(2*N)
        XK2(N) = XK(2*N-1)-XK(2*N)

C       NOW TEST TO SEE IF XK2 IS REALLY ZERO TO THE LIMIT OF THE
C       MACHINE ACCURACY  = 1 .E -30
C       XK2 IS THE COEFFICEINT OF THE GROWING EXPONENTIAL AND MUST
C       BE TREATED CAREFULLY

        IF(XK2(N) .EQ. 0.0) GO TO 28
c        IF (ABS (XK2(N)/XK(2*N-1)) .LT. 1.E-30) XK2(N)=0.0

        IF (ABS (XK2(N)/(XK(2*N-1)+1.e-20)) .LT. 1.E-30) XK2(N)=0.0   ! For debug only (with -Ktrap=fp option)


   28 CONTINUE
 
      RETURN
      END